Algorithm/세그먼트 트리 (Segment Tree)
[BOJ] 2357 최솟값과 최댓값
노는게제일좋아!
2019. 9. 10. 11:32
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문제: https://www.acmicpc.net/problem/2357
소스 코드:
#include <iostream>
#include <string.h>
#include <queue>
#include <functional>
#include <algorithm>
#define SIZE 100001*4
#define MAX 1000000000
using namespace std;
int n,m,large[SIZE], small[SIZE];
int large_update(int pos,int val,int x,int y,int node)
{
if (pos > y || pos < x) return large[node];
if (x == y) return large[node]=val;
int mid = (x + y) >> 1;
return large[node] = max(large_update(pos, val, x, mid, node * 2), large_update(pos, val, mid + 1, y, node * 2 + 1));
}
int small_update(int pos, int val, int x, int y, int node) {
if (pos > y || pos < x) return small[node];
if (x == y) return small[node] = val;
int mid = (x + y) >> 1;
return small[node] = min(small_update(pos, val, x, mid, node * 2), small_update(pos, val, mid + 1, y, node * 2 + 1));
}
int small_query(int hi,int low,int x,int y,int node)
{
if (y<low || x>hi) return MAX;
if (low <= x&&hi >= y) return small[node];
int mid = (x + y) >> 1;
return min(small_query(hi, low, x, mid, node * 2), small_query(hi, low, mid + 1, y, node * 2 + 1));
}
int large_query(int hi, int low, int x, int y, int node)
{
if (y<low || x>hi) return 0;
if (low <= x&&hi >= y) return large[node];
int mid = (x + y) >> 1;
return max(large_query(hi, low, x, mid, node * 2), large_query(hi, low, mid + 1, y, node * 2 + 1));
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(NULL), cout.tie(NULL);
cin >> n >> m;
fill(small, small + n * 4 + 1, MAX);
int temp;
for (int i = 0; i < n; i++)
{
cin >> temp;
small_update(i, temp, 0, n - 1, 1);
large_update(i, temp, 0, n - 1, 1);
}
int q, w;
for (int i = 0; i < m; i++)
{
cin >> q >> w;
cout<<small_query(w-1,q-1, 0, n - 1, 1)<<' '
<<large_query(w-1,q-1, 0, n - 1, 1)<<'\n';
}
return 0;
}
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